Question

Решите уравнения 12x^2-(4x-3)(3x+1)=-2,
(4x-3)(3+4x)-2x(8x-1)=0,
X+(5x+2)^2=25(1+x^2):
^2 - во второй степени.

Answer 1

12x^2-12x^2-4x+9x+3+2=0
5x=-5
x=-1

2/16x^2-9-16x^2+2x=0
2x=9
x=4.5

3/x+25x^2+20x+4-25-25x^2=0
21x=21
x=1