Question

найдите производную функции у=(1/7-3 х^2)^35

Answer 1

у'=((1/7-3 х^2)^35)'=35(1/7-3 х^2)^34*(1/7-3 х^2)'=35(1/7-3 х^2)^34*(-6 x)=-210x(1/7-3 х^2)^34