Question

z1=-2+7i,z2=3-3i помогите пож

Answer 1

z1+z2=-2+7i+3-3i=1+4i
z1-z2=-2+7i-3+3i=-5+10i
z1*z2=(-2+7i)*(3-3i)=-6+6i+21i-21i²=-6+27i+21=15+27i
z1/z2=(-2+7i)/(3-3i)=(-2+7i)*(1+i)/3/(1-i)/(1+i)=(-2+7i-2i+7i²)/3/(1-i²)=(-2+5i-7)/3/2=(-9+5i)/6=-9/6+5/6i=-1,5+5/6i