Question

(x+1)^+(x+1)=6
решите буду вам благодарна)

Answer 1

x^2 + 2x + 1 + x + 1 - 6 = 0
x^2 + 3x - 4 = 0
(x + 4)(x - 1) = 0
x1 = -4; x2 = 1