Question

Log₃$frac{1}{81}$+log₂√2-4°

Answer 1

log₃(1/81)+log₂√2-4°=log₃(1/3)⁴+log₂2¹/²-1=log₃3⁻⁴-1=-4*log₃3+(1:(1/2))*log₂2-1=-4+2-1=-3