Question

решите уравнения sin2x=√3cos x

Answer 1

sin2x = √3cosx
2sinx*cosx = √3cosx |:cosx ≠0
2sinx = √3
sinx = √3/2
sinx = (-1)^k arcsin √3/2 + πk
sinx = (-1)^k π/3 + πk, k∈z