Question

Сроооочно плиз x2 -y2=16 и x-y+2=0 решите систему

Answer 1

$left { {{x^2-y^2=16,} atop {x-y+2=0;}} right. left { {{(x-y)(x+y)=16,} atop {x-y=-2;}} right. left { {{-2(x+y)=16,} atop {x-y=-2;}} right. left { {{x+y=-8,} atop {x-y=-2;}} right. left { {{2x=-10,} atop {y=x+2;}} right. \ left { {{x=-5,} atop {y=-3.}} right.$

Answer 2

Блин не успел