Question

1)5x+3(3x+7)=35
2)8x-(7x+8)=9
3)8y-9-(4y-5)=12y-(4+5y)
4)4+8y+8=2y-(10+7y)+9

Answer 1

$1. quad 5x+3(3x+7) = 35\ \ 5x + 9x + 21 = 35 \ \ 14x = 14\ \ x = 1$

$2. quad 8x - (7x + 8) = 9 \ \ 8x - 7x - 8 = 9 \ \ x = 8+9\ \ x = 17$

$3. quad 8y - 9 - (4y-5) = 12y - (4+5y) \ \ 8y - 9 - 4y + 5 = 12y - 4 - 5y\ \ 4y -4 = 7y - 4\ \ 3y = 0 \ \ y = 0$

$4. quad 4 + 8y + 8 = 2y - (10+7y) +9\ \ 12+8y = 2y - 10 - 7y + 9\ \ 12 + 8y = -5y - 1 \ \ 13y = -13 \ \ y = -1$