Question

х-5у=2; х^2-y=10; решить систему

Answer 1

{x - 5y = 2

{x^2 - y = 10

 

x = 2 - 5y

(2 - 5y)^2 - y = 10

4 + 25y^2 - 20y - y - 10 = 0

25y^2 - 21y - 6 = 0

D=(−21)2−4·25·(−6)=441+600=1041

y1=(21 +√1041)/50
y2=(21 -√1041)/50

 

x1 = 2 - (21 +√1041)/10

x2 = 2 - (21 -√1041)/10