Question

помогите решить 1)cos (arcsin 1/2)-arccos 1 2) cos(3arctg корень 3-arccos(-1/2))

Answer 1

$1)~~ cos(arcsin0.5)-arccos 1=cos frac{pi}{6}-0= frac{sqrt{3}}{2}$

$2)~~ cos (3arctg sqrt{3} -arccos(-1/2))=cos(3cdot frac{pi}{3}- frac{2 pi }{3})=cos frac{pi}{3}=0.5$