Question

Сократительной дробь t^2-366+t
9+12z+16z^227-64z^3
27a^3+82+3a

Answer 1

$frac{t^2-36}{6+t}= frac{(t-6)(t+6)}{t+6}=t-6\ frac{9+12z+16z^2}{27-64z^3} = frac{9+12z+16z^2}{(3-4z)(9+12z+16z^2)}= frac{1}{3-4z} \ frac{27a^3+8}{2+3a} = frac{(3a+2)(9a^2+6a+4)}{3a+2} = 9a^2+6a+4$