Question

Решить неравенство:
$x+3 textless (x+1)^{2}$

Answer 1

$x+3 textless (x+1)^{2}\x+3 textless x^2+2x+1\x^2+x-2 textgreater 0\x^2+x-2=0\x_{1,2}=frac{-1^+_-sqrt{9}}{2}=frac{-1^+_-3}{2}\x_1=1 ;x_2=-2\(x-1)(x+2) textgreater 0\///(+)///(-2)...(-)...(1)///(+)/// textgreater x\xin(-infty;-2)cup(1;+infty)\OTBET:x textless -2;x textgreater 1$