Question

Сократите дробь
1) a^2+a/a^3+a^2
2) 3p+6q/p^2+2pq
3)8m-8n/9n-9m
4)3x^3+3xy^2/6yx^2+6y^3

Answer 1

$frac{a^2+a}{a^3+a^2}=frac{a(a+1)}{a^2(a+1)}=frac{1}{a}\frac{3p+6q}{p^2+2pq}=frac{3(p+2q)}{p(p+2q)}=frac{3}{p}\frac{8m-8n}{9n-9m}=frac{8(m-n)}{9(n-m)}=frac{8}{9}\frac{3x^3+3xy^2}{6yx^2+6y^3}=frac{3x(x^2+y^2)}{6y(x^2+y^2)}=frac{x}{2y}$

Answer 2

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Answer 3

1) (a^2+a)/(a^3+a^2)=a(a+1)/a²(a+1)=1/a
2) (3p+6q)/(p^2+2pq)=3(p+2q)/p(p+2q)=3/p
3)(8m-8n)/(9n-9m)=-8(n-m)/9(n-m)=-8/9
4)(3x^3+3xy^2)/(6yx^2+6y^3)=3x(x²+y²)/6y(x²+y²)=3x/6y=x/2y