Question

решите пожалуйста даю 100 б
x^2y^2-1
25-36p^2c^2
4-c^2d^2
49x^2y^2-400

Answer 1

$x^2y^2-1=(xy-1)(xy+1)\25-36p^2c^2=(5-6pc)(5+6pc)\4-c^2d^2=(2-cd)(2+cd)\49x^2y^2-400=(7xy-20)(7xy+20)$

Answer 2

Решение
x^2y^2-1 = (xy - 1)(xy + 1)
25-36p^2c^2 = 5² - (6pc)² = (5 - 6pc)(5 + 6pc)
4-c^2d^2 = (2 - cd)(2 + cd)
49x^2y^2-400 = (7xy)² - 20² = (7xy - 20)(7xy + 20)