Question

$frac{3p^4}{5q^8} * frac{15q^2(p-5)^2}{21p^2} : frac{3p^2(5-p)}{7q^6} = ?$

Answer 1

$frac{3p^4}{5q^8} cdot frac{15q^2(p-5)^2}{21p^2} : frac{3p^2(5-p)}{7q^6} = \ \ =frac{3p^4}{5q^8} cdot frac{15q^2(5-p)^2}{21p^2} cdot frac{7q^6}{3p^2(5-p)}= 5-p$