Question

5x-18<3(x+2) , 4x-8>3x-12

Answer 1

$left { {{5x-18 textless 3x+6} atop {4x-8 textgreater 3x-12}} right. \ left { {{5x-3x textless 6+18} atop {4x-3x textgreater -12+8}} right. \ left { {{2x textless 24} atop {x textgreater -4}} right. \ left { {{x textless 12} atop {x textgreater -4}} right.$
Получаем интервал: x∈(-4; 12)

Answer 2

Да благодарю!!!

Answer 3

На здоровье и удачи ))