Question

Разложите на множители квадратный трѐхчлен
-6x^2-17x+3

Answer 1

6x^2+17x-3=0;
D=289+72=361;
x=-3;x=1/6;
-6x^2+17x-3=-6(x+3)(x-1/6)=(x+3)(1-6x)

Answer 2

$-6x^2-17x+3=? \ Delta=(-17)^2+24*3=289+72=361 \ x_1= frac{17-19}{-12}= frac{1}{6} \ x_2= frac{17+19}{-12} =-3 \ \ underline{-6x^2-17x+3=-(x+3)(6x-1)}$