Предмет: Алгебра, автор: feevni

Найдите наибольшее и наименьшее значение функции f(x)=2x^3-9x^2+12x-7 на отрезке [0;3]

Ответы

Автор ответа: Аноним

0

f`(x)=6x²-18x+12=6(x²-3x+2)=0
x1+x2=3 U x18x2=2
x1=1∈[0;3]
x2=2∈[0;3]
f(0)=-7 наим
f(1)=2-9+12-7=-2
f(2)=16-18+24-7=15 наиб
f(3)=54-81+36-7=2

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