Question

(3x-1)(x+3)=x(1-6x) 
решите

Answer 1

$(3x-1)(x+3)=x(1-6x) \ 3x^2+9x-x-3=x-6x^2 \ 9x^2+7x-3=0 \ Delta=49+108=157 \ sqrt{Delta}= sqrt{157}=12,52 \ x_1= frac{-7-12,52}{18} = -frac{19,52}{18}=-1,08 \ x_2= frac{-7+12,52}{18}= frac{5,52}{18}=0,3$