Question

arcsin(3-2x)=n/4
решить уравнение

Answer 1

$arcsin(3-2x)=frac{pi}{4}$

$3-2x=sinfrac{pi}{4}$

$3-2x=frac{sqrt{2}}{2}$

$-2x=frac{sqrt{2}}{2}-3$

$2x=3-frac{sqrt{2}}{2}$

$x=1,5-frac{sqrt{2}}{4}$