Question

293 Найти корни уравнения
а) |x^2+3x-1|=3x

Answer 1

$|x^2+3x-1|=3x \ left { {3x geq 0} atop {left[array x^2+3x-1=3x \ x^2+3x-1=-3x end{array}right.}} right. \ left { {x geq 0} atop {left[array x^2-1=0 \ x^2+6x-1=0 end{array}right.}} right. \ left { {x geq 0} atop {left[array x^2=1 \ D_1=3^2+1cdot1=10 end{array}right.}} right. Rightarrow left { {x geq 0} atop {left[array x=pm1 \ x= -3pm sqrt{10} end{array}right.}} right. Rightarrow left[array x=1 \ x= -3+sqrt{10} end{array}right.}$
Ответ: $1$ и $-3+sqrt{10}$

Answer 2

спасибо