Question

Помогите, пжл, решить:
cos^2x-|sinx|+1=0

Answer 1

$cos^2x + 1 = |sinx| \ 1 leq cos^2x+1 leq 2; 0 leq |sinx| leq 1; = textgreater \ = textgreater left { {cosx = 0} atop {|sinx| = 1}} right. x = pi /2 + pi n$