Question

решите неравенство(1:8)^5x-17 < 64

Answer 1

$(frac{1}{8})^{5x-17} textless 64 \ \ (8^{-1})^{5x-17} textless 8^2 \ \ 8^{-5x+17} textless 8^2 \ \ -5x+17 textless 2 \ \ -5x textless -15 \ \ x textgreater 3$