Question

Разложите на множители
5ax в квадрате - 10ах - bx + 2b -x + 2

Answer 1

5ax(x-2)-b(x-2)-(x-2)=(x-2)(5a-b-1)

Answer 2

5ax^2-10ax-bx+2b-x+2=
=5ax*(x-2)-b*(x-2)-1*(x-2)=
=(5ax-b-1)*(x-2)
Ответ: (5ax-b-1)*(x-2).