Question

решить функцию  х^2-у^2=8 х-у=4!

Answer 1

$x=4+y \ \ (4+y)^2-y=8 \16 +8y+y^2 -y^2=8 \ \ 8y=-8; y =-1 \\ x=4+(-1)=4-1=3 \ \ \ (3;-1)$