Question

(1/√2)^х^3-9х=1. помогите решить

Answer 1

$( frac{1}{ sqrt{2} })^{x^3-9x} =1 \ ( frac{1}{ sqrt{2} })^{x^3-9x}= (frac{1}{ sqrt{2} })^0 \ x^3-9x=0 \ x(x^2-9)=0 \ x(x-3)(x+3)=0 \ x=0 \ x-3=0 Rightarrow x=3 \ x+3=0 Rightarrow x=-3 \ x_1=-3;x_2=0;x_3=3$