Question

$14 x^{2} + x-3=0$

Answer 1

14x^2+x-3=0
D = b²-4ac = 1²-4*14(-3) = 1+168 = 169 = 13²
$x_{1} = frac{-b+ sqrt{D} }{2a} = frac{-1+13}{2*14} = frac{12}{28} = frac{3}{7}$$x_{2} = frac{-b- sqrt{D} }{2a} = frac{-1-13}{2*14} = -frac{14}{28} = - frac{1}{2} = - 0.5$