Question

разложите на множители
1)x³-9x
2)-5a²-10ab-5b²

Answer 1

$x^3-9x=x(x^2-9)=x(x^2-3^2)=x(x-3)(x+3)\\-5a^2-10ab-5b^2=-5(a^2+2ab+b^2)=-5(a+b)^2$

Answer 2

$1) x^{3} -9x=x( x^{2} -9)=x(x-3)(x+3) \ \ 2)-5a ^{2} -10ab-5b ^{2} =-5(a ^{2} +2ab+b ^{2} )=-5(a+b) ^{2}$