Question

Математика,Помогите решить 2 задания!

Answer 1

y'=(x³+x²+x)'=3x²+2x+1

S₀¹(x²+x+2)dx=(x²⁺¹/(2+1)+x¹⁺¹/(1+1)+2*x)|₀¹=(x³/3+x²/2+2*x)|₀¹=(1³/3+1²/2+2*1)-(0/3+0/2+2*0)=1/3+1/2+2=5/6+2=2 целых 5/6