Question

Разложите на множители:а)18х^2-27ху+14хс-21ус;
б)(х-у)+(х-у )^2

Answer 1

$18x^2-27xy+14xc-21yc=9x(2x-3y)+7c(2x-3y)=\\=(2x-3y)(9x+7c)\\(x-y)+(x-y)^2=(x-y)+(x-y)(x-y)=(x-y)(1+x-y)$

Answer 2

а) 18x²-27xy+14xc-21yc= 9x(2x-3y)+7c(2x-3y)= (2x-3y)(9x+7c)

б) (x-y)+(x-y)²=(x-y)(1+x-y)