Предмет: Физика, автор: NarineSim2000

алюминиевый проводник площадью поперечного сечения 11,25 мм(в квадрате) заменили медным проводником такой же длины и сопротивления.каким должно быть поперечное сечение медного провода?

Ответы

Автор ответа: larisaorlova65
3
L₁ =L₂, R₁=R₂, S₁=11,25 мм², ρ₁ =0,028 Ом*мм²/м,   ρ₂=0,017
R=ρ *L/S
ρ₁L₁/S₁ =ρ₂L₂/S₂
S₂ =ρ₂L₂S₁/ρ₁L₁=ρ₂S₁/ρ₁
S₂=0,017*11,25/0,028 =6,83 мм²
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