Question

Решите уравнение:

1) (3x+1)^2-(3x-1)^2=11x+1,2

2)(5+2y)(y-3)-2(y-1)^2=0

Answer 1

9x^2+6x+1-9x^2+6x-1=11x+1.2

12x-11x=1.2

x=1.2

 

 

5y-15+2y^2-6y-2y^2+4y-2=0

3y=17

y=17/3