Question

Найдите значение выражения
(1/3a + 1/6a)*a^2/5 при а=-2,7

Answer 1

$(\frac{1}{3a}+\frac{1}{6a})*\frac{a^2}{5}= [tex](\frac{2}{6a}+\frac{1}{6a})*\frac{a^2}{5}= [tex]\frac{1}{2a}*\frac{a^2}{5}=\frac{a}{10}=\frac{-2,7}{10}=-0,27$