Question

8a-40/4a^2-100 сократите дробь

Answer 1

(8а-40) / (4а²-100) = 8 (а-5) / 4 (а-5)(а+5) = 2 /(а+5)

Answer 2

$\frac{8a-40}{4a ^{2}-100 } = \frac{4(2a-10)}{4(a ^{2} -25)} = \frac{2a-10}{a ^{2}-25 } = \frac{2(a-5)}{(a-5)(a+5)} = \frac{2}{a+5}$