Question

log5 (x-10)=2+log5 2 Найдите корень уравнения

Answer 1

$log_{5} (x-10)=2+log_{5}2$

ОДЗ:
$x-10\ \textgreater \ 0$

$x\ \textgreater \ 10$

$log_{5} (x-10)= log_{5}5^2 +log_{5}2$

$log_{5} (x-10)= log_{5}25 +log_{5}2$

$log_{5} (x-10)= log_{5}(25*2)$

$log_{5} (x-10)= log_{5}50$

$x-10=50$

$x=60$

Ответ: 60