Question

log25 log32 log6 36

Answer 1

$log_{25}log_{32}log_{6}36=log_{5^{2}}log_{2^{5}}log_{6}6^2= \frac{1}{2} log_{5} \frac{1}{5} log_{2}2log_{6}6=\frac{1}{2} log_{5} \frac{1}{5} log_{2}2$
$=\frac{1}{2} log_{5}5^{-1}=-\frac{1}{2} log_{5}5=-\frac{1}{2}=-0,5$