Question

Помогите решить, пожалуйста

Answer 1

(b²-16b+64)/(b-8)=(b-8)²/(b-8)=b-8

Answer 2

$\frac{b^{2}-10b}{b-8}+ \frac{6b-64}{8-b}=\\ = \frac{b^{2}-10b}{b-8}-\frac{6b-64}{b-8}=\\ = \frac{b^{2}-10b-6b+64}{b-8}=\\ = \frac{b^{2}-16b+64}{b-8}=\\ = \frac{(b-8)^2}{b-8}=\\ =b-8$