Question

x>0; reshite uravneni

Answer 1

  $x^{\sqrt{y}} = y \\ y^{\sqrt{y}}=x^4 \\\\ \sqrt{y}*lnx=lny\\ \sqrt{y}lny = 4*lnx \\\\ \frac{lnx}{lny} = +-\frac{1}{2}\\ x^2=y\\ \frac{1}{x^2}=y\\\\ x^2=y\\ ( x=1;2) \\ (y=1;4) \\\\ \frac{1}{x^2} = y \\ x^{\frac{1}{x}}=\frac{1}{x^2}$ 
     
   $x=y=1$