Question

Найдите значения выражения. (√6-3√2) (√6+3√2)

Answer 1

(a-b)(a+b)=a^2-b^2
(√6)^2-(3√2)^2=6-9*2=6-18=-12

Answer 2

(a-b)(a+b)=a²-b²

$( \sqrt{6} - 3\sqrt{2} )( \sqrt{6} +3\sqrt{2} )=( \sqrt{6} )^2-(3\sqrt{2})^2=6-3^2*(\sqrt{2} )^2= \\ =6-9*2=6-18=-12$