Question

С решением,пожалуйста!

Answer 1

$| 8x+13| \leq 4$

$\left \{ {{8x+13 \leq 4} \atop {8x+13 \geq -4}} \right.$

$\left \{ {{8x \leq -9} \atop {8x \geq -17}} \right.$

$\left \{ {{x \leq - \frac{9}{8} } \atop {x \geq - \frac{17}{8} }} \right.$

$\left \{ {{x \leq -1 \frac{1}{8} } \atop {x \geq -2 \frac{1}{8} }} \right.$

Ответ: $[-2 \frac{1}{8} ;-1 \frac{1}{8} ]$