Question

Розв'язати рівняння
5 sin(2x-pi/6)-5=0

Answer 1

5 sin (2x -π/6) -5=0
5 (sin(2x -π/6) -1) =0
sin(2x -π/6) -1=0
sin(2x -π/6)=1
2x-π/6 =π/2 +2πn, n∈Z
2x=π/6 +π/2 +2πn, n∈Z
2x=4π/6 + 2πn, n∈Z
x =4π/12 + πn, n∈Z
x=π/3 +πn, n∈Z
Ответ: π/3 +πn, n∈Z.