Question

Обчисліть 2 log2 1/4 + 3 log3 27

Answer 1

$2log_{2} \frac{1}{4} + 3log_{3}27 = 2log_{2}2^{-2} + 3log_{3}3^{3} =$
$2*(-2)*log_{2}2+ 3*3*log_{3}3 = -4*1 +9*1 = -4+9 = 5$

Answer 2

$2lo g_{2} \frac{1}{4} +3log _3} 27=2log _{2} 2 ^{-2} +3log _{3} 3 ^{3} = \\ =-2*2log _{2} 2+3*3log _{3} 3=-2*2*1+3*3*1= \\ =-4+9=9-4=5$