Question

решите уравнение (2х+1)^2=25

Answer 1

$(2x+1) ^{2} =25 \\ 4 x^{2} +1+4x-25=0 \\ 4 x^{2} +4x-24=0/:4 \\ x^{2} +x-6=0\\D=1+24=25 \\ \sqrt{D} =5 \\ x_{1} = \frac{-1+5}{2} = \frac{4}{2} =2 \\ x_{2} = \frac{-1-5}{2} =- \frac{6}{2} =-3$