Question

Логарифмы, вычислить

Answer 1

Смотреть во вложении

Answer 2

$((1- log^2_{2}7 ) log_{14}2 + log_{2}7)* 3^{log_{3}14 } =$$( (1- log_{2} 7) (1+log_{2} 7)* log_{14} 2+ log_{2} 7)*14=$$(( log_{2}2 - log_{2} 7)( log_{2}2 + log_{2} 7)* log_{14} 2+log_{2} 7)*14=$$( log_{2} \frac{2}{7} * log_{2}14* log_{14} 2+ log_{2} 7)*14=$$( log_{2} \frac{2}{7} + log_{2} 7)*14= log_{2} ( \frac{2}{7} *7)*14=14$