Question

найдите область определения функций y=√(12-x^2-x)/√(x+3)

Answer 1

$y= \frac{ \sqrt{12- x^{2} -x} }{ \sqrt{x+3} }$

$\left \{ {{- x^{2} -x+12 \geq 0} \atop {x+3\ \textgreater \ 0}} \right.$

$\left \{ {{ x^{2} +x-12 \leq 0} \atop {x\ \textgreater \ -3}} \right.$

$D=1+48=49$
$x_1=3$
$x_2=-4$

$\left \{ {{(x-3)(x+4) \leq 0} \atop {x\ \textgreater \ -3}} \right.$

$D(y)=(-3;3]$