Question

помогите))
0.5 sin4x+0.5=    0

Answer 1

$0.5\sin 4x+0.5=0|:0.5\\ \sin 4x+1=0\\ \sin 4x=-1\\ 4x=- \frac{\pi}{2}+2\pi k,k \in Z\\ x=- \frac{\pi}{8}+ \frac{\pi k}{2}, k \in Z$

Answer 2

0.5sin4x=-0.5
sin4x=-1
4x=-π/2+2πn, n∈Z
x=-π/8+$\frac{ \pi n}{2}$, n∈Z