Question

(а^2+2аb+b^2):(a+b)=
(a(a+3)+2a(3+a)):3a=

Answer 1

$\\\frac{a^2+2ab+b^2}{a+b}= \frac{(a+b)^2}{a+b} = a + b\\ \\\frac{a(a+3)+2a(3+a)}{3a} = \frac{a(a+3+2*(3+a)}{3a} = \frac{a + 3 + 6 + 2a}{3} = \frac{3a+9}{3}=\\=\frac{3(a+3)}{3} = a+3$