Предмет: Физика, автор: akira221555

Два резистора R1= 15 Ом и R2= 10 Ом соединены последовательно, напряжение на первом резисторе рано 60 В. Чему равно напряжение на втором резисторе?

Ответы

Автор ответа: awkut

1

закон Ома
I = U1/R1 = 60/15 = 4 A
U2 = I*R2 = 4*10 = 40 B

akira221555: спасибо

Автор ответа: larisaorlova65

1

При последовательном соединении сила тока I=I₁ =I₂ =const,
поэтому U₁/R₁=U₂/R₂ ⇒ U₂ =U₁R₂/R₁,
U₁ =60*10/15 =40B

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