Question

найдите разность  $frac{48x^2}{6x+4}-8x$

Answer 1

$frac{48x^2}{6x+4}-8x=frac{48x^2}{6x+4}-frac{8x(6x+4)}{6x+4}=frac{48x^2}{6x+4}- frac{48x^2+32x}{6x+4}=-frac{32x}{2(3x+2)}= \ =-frac{16x}{3x+2}$