Question

 sin^2x+ѵ2sinx=0
rewiteeeee pliiiiiiz

Answer 1

sin^2x + √2*sinx = 0 
sinx * ( sinx +√2) = 0 

sinx =  0 ==> x = pik, k ∈ Z
sinx = - √2 ==> ∉ [ - 1; 1]  нет реш 

Ответ:
x = pik, k ∈ Z

Answer 2

$sin ^{2} x+ \sqrt{2} sinx=0\\sinx(sinx+ \sqrt{2} )=0\\sinx=0\\x= \pi n\\\\sinx \neq - \sqrt{2}$